-x^2+2x=35

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Solution for -x^2+2x=35 equation:


Simplifying
-1x2 + 2x = 35

Reorder the terms:
2x + -1x2 = 35

Solving
2x + -1x2 = 35

Solving for variable 'x'.

Reorder the terms:
-35 + 2x + -1x2 = 35 + -35

Combine like terms: 35 + -35 = 0
-35 + 2x + -1x2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
35 + -2x + x2 = 0

Move the constant term to the right:

Add '-35' to each side of the equation.
35 + -2x + -35 + x2 = 0 + -35

Reorder the terms:
35 + -35 + -2x + x2 = 0 + -35

Combine like terms: 35 + -35 = 0
0 + -2x + x2 = 0 + -35
-2x + x2 = 0 + -35

Combine like terms: 0 + -35 = -35
-2x + x2 = -35

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -35 + 1

Reorder the terms:
1 + -2x + x2 = -35 + 1

Combine like terms: -35 + 1 = -34
1 + -2x + x2 = -34

Factor a perfect square on the left side:
(x + -1)(x + -1) = -34

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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